Kamil Baczman

1. Let user change any of two live.numbox

I managed to update the result after either live.numbox changes by packing them into list with `pak`. What I'm know experiencing is that every time patcher starts, the add operation gets the value of whatever live.numbox sends its value first and then performs addition - using for the second value whatever number is supplied as `pak` argument as default one. Example:

1. Patcher starts, live.numbox1 = 11, live.numbox2 = 5

2. `pak` object gets value of first live.numbox1 = 11

2. `pak` object gets value of first live.numbox2 = 5

1. Patcher starts, live.numbox1 = 11, live.numbox2 = 5 

I tried to synchronize both values by using for example `buddy` and this somehow resolves initial problem of non-complete input list but it creates another problem. If user changes live.numbox1, then he has also to change live.numbox2 and vice versa in order for `buddy` two have both messages at its inlets every time.

I hope I explained this clearly. I'm attaching also gif showing the problem and patcher data.

maxadd.gif

test.amxd

Hi, I want to construct simple logic:
1. Let user change any of two live.numbox
2. Add them and print the result

I managed to update the result after either live.numbox changes by packing them into list with `pak`. What I'm know experiencing is that every time patcher starts, the add operation gets the value of whatever live.numbox sends its value first and then performs addition - using for the second value whatever number is supplied as `pak` argument as default one.  Example:

1. Patcher starts, live.numbox1 = 11, live.numbox2 = 5
2. `pak` object gets value of first live.numbox1 = 11
3. `pak` object emits list [11 0]
4. `add` performs 11+0 = 11
2. `pak` object gets value of first live.numbox2 = 5
3. `pak` object emits list [11 5]
4. `add` performs 11+5 = 16

1. Patcher starts, live.numbox1 = 11, live.numbox2 = 5 
2. `add` somehow gets immediately [11 5]
3. `add` performs 11+5 = 16

Hi, I want to construct simple logic:
1. Let user change any of two live.numbox
2. Add them and print the result
I managed to update the res

add-two-live-numbox-but-only-after-both-are-received

You could initially disable output of the items

and use loadbang with some delay to enable them.

That can be done for example using a gate - shown at left

Screen shot 2020-10-02 at 5.07.23 PM.png

You could initially disable output of the items
and use loadbang with some delay to enable them.
That can be done for example using a gate - shown at left
Or smooth the output like at the right 


Add two live.numbox but only after both are received