I want to manage 2 expr in one [jit.expr] object ... without success

jit.expr @expr "((cell[0]*0.1)*2.)-1." "((cell[0]*0.1)*1.5)-0.75"

jit.expr @expr "((cell[0]*0.1)*1.5)-0.75"

jit.expr @expr (((cell[0]*0.1)*2.)-1.) (((cell[0]*0.1)*1.5)-0.75)

jit.expr @expr ((cell[0]*0.1)*2.)-1. ((cell[0]*0.1)*1.5)-0.75

I want to manage 2 expr in one [jit.expr] object ... without success
Could anyone give help.

This:
jit.expr @expr "((cell[0]*0.1)*2.)-1." "((cell[0]*0.1)*1.5)-0.75"
does not work

but this:
jit.expr @expr "((cell[0]*0.1)*2.)-1."
with
jit.expr @expr "((cell[0]*0.1)*1.5)-0.75"
packed inside [jit.pack 2] , work nice.

In Max5 I tryed:
jit.expr @expr (((cell[0]*0.1)*2.)-1.) (((cell[0]*0.1)*1.5)-0.75)
jit.expr @expr "((cell[0]*0.1)*2.)-1." "((cell[0]*0.1)*1.5)-0.75"
jit.expr @expr ((cell[0]*0.1)*2.)-1. ((cell[0]*0.1)*1.5)-0.75

another-expr-issue

the side with [expr] is good but my [jit.expr] gives bas result.

Here's a similar problem.
the side with [expr] is good but my [jit.expr] gives bas result.

aren't you looking for in[0] instead of cell[0]?


I want to multiply the expr by its inverse, no success within one [jit.expr],

and I don't want the [jit.op @op * @val -1.]

I want to multiply the expr by its inverse, no success within one [jit.expr],
and I don't want the [jit.op @op * @val -1.]

 represent negative values by black... which is the reason why it gives the impression of not working properly.

jit.expr @expr "(in[0] * -1.)" just works fine. jit.pwindow represent negative values by black... which is the reason why it gives the impression of not working properly.


So the inverse would be @expr "abs(norm[0] *-1.)"

another expr issue