gammon

Can anybody tell me how long the max. length of buffer~ object is ?

I tried to load a audifole wir 1h50min and got the message "out of menory"

is there a work around to load long audiofiles ?

Can anybody tell me how long the max. length of buffer~ object is ?
I tried to load a audifole wir 1h50min and got the message "out of menory"

buffer-7

sorry, but i dont get your 44100*32*6600 example.

but i would like to "edit" the file with waveform~

Basically, if the buffer size exceeds the amount of free RAM you have available, you won't be able to load it into your RAM. In such a case (and in general with long files), the recommended method is to use sfplay~.

You should consider that Max is not really meant as a standalone editing platform for audio such as Audacity, Peak, etc.

Basically, if the buffer size exceeds the amount of free RAM you have available, you won't be able to load it into your RAM.  In such a case (and in general with long files), the recommended method is to use sfplay~.

You should consider that Max is not really meant as a standalone editing platform for audio such as Audacity, Peak, etc.  

44100*6600*32 = 9 313 920 000 Bytes = 9.3 GB,

This calculation is correct on OSX v10.6. Otherwise 9 313 920 000 should be divided by 1024 x 1024 x 1024 and you'll get to a little lower 8.67 GB. In the case of mono.

Quote:44100*6600*32 = 9 313 920 000 Bytes = 9.3 GB, 

This calculation is correct on OSX v10.6. Otherwise 9 313 920 000 should be divided by 1024 x 1024 x 1024 and you'll get to a little lower 8.67 GB. In the case of mono.


Of course i know that Max is not Protools.

For the Applikation i´m building it would be very helpfull to have very basic (cut, crop, save file) edit functions for non-audioexperts.

So this should be enough to load a File with 1GB.

If somebody wants to see my (not finished) Applikation, and give me some feedback:

Thank you all.
Thanks for the math tutoring.

anyway:
I have 4GB of RAM. in my MacBook.
So this should be enough to load a File with 1GB.

If somebody wants to see my (not finished) Applikation, and give me some feedback:
www.eigentone.com/RadioRecorder/

vanille béchamel wrote on Wed, 11 November 2009 23:39

44100*6600*32 = 9 313 920 000 Bytes = 9.3 GB

vanille béchamel wrote on Wed, 11 November 2009 23:39
44100*6600*32 = 9 313 920 000 Bytes = 9.3 GB
(44100 hz , 6600 seconds, 32 Bytes).

I think you meant bit, not byte.
32 bits = 4 bytes


, especially the portion on consumer confusion. Basically a kilo in the binary system is 1024.

Quote:1024 x 1024 x 1024 ? can you explain ?

Read it here, especially the portion on consumer confusion. Basically a kilo in the binary system is 1024.