$adam

I need to get somehow the directory where the current patcher (the one 

containing my mxj object) is stored (I have an xml with default settings 

for my object, and I would like to place this in the same directory as 

the Max patch itself). Using System.getProperty("user.dir"), I get the 

root folder of my filesystem (I'm on OS X 10.4.10) if executed from mxj, 

while in Eclipse I get the current runtime folder (as expected). Is 

there some mxj-specific solution for this? Also, is there any mxj method 

to get the current Max/MSP installation path?

I need to get somehow the directory where the current patcher (the one 
containing my mxj object) is stored (I have an xml with default settings 
for my object, and I would like to place this in the same directory as 
the Max patch itself). Using System.getProperty("user.dir"), I get the 
root folder of my filesystem (I'm on OS X 10.4.10) if executed from mxj, 
while in Eclipse I get the current runtime folder (as expected). Is 
there some mxj-specific solution for this? Also, is there any mxj method 
to get the current Max/MSP installation path?

________________
Siska Ádám
+36 (70) 207-63-85
http://apocalypse.rulez.org/~sadam


how-to-get-the-current-directory

a "filepath" object with "default" argument

The previews one don't work.
This seems to be the way


Thanks sandoval31 - one of the things I was looking for!

This is too late to be useful to the OP, but I think the answer he/she wanted was something along these lines (untested).

public class MyMaxObject extends MaxObject{

  public MyMaxObject(){
    String mainPatcherPath = this.getParentPatcher().getFilePath();
    post(mainPatcherPath); // prints the location of the patcher containing the mxj object
  }
}


How to get the current directory