Jean-Francois Charles

impossible-to-use-p-operator-in-jit-expr

A workaround is obvious : expr "in[0]*(in[0]>0.3)", for example. Anyway, the

A workaround is obvious : expr "in[0]*(in[0]>0.3)", for example. Anyway, the
question remains.


i can confirm >p jit.expr behavior on xp/pc (before those shiny new macs i 

i can confirm >p jit.expr behavior on xp/pc (before those shiny new macs i 
thought its enough to say 'xp')

if i understood the problem correctly,
one workaround could be:

The ">p" infix operator doesn't work with the jit.expr parser. 

However the prefix gtp(x,y) "greater than pass" should work (haven't 

verified, but programmed it to work that way). Similar for other 

The ">p" infix operator doesn't work with the jit.expr parser.  
However the prefix gtp(x,y) "greater than pass" should work (haven't  
verified, but programmed it to work that way). Similar for other  
logical pass operators.

impossible to use >p operator in jit.expr?