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		<title>Cycling 74  &#187;  Topic: jit.dimmap ?</title>
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		<pubDate>Wed, 19 Jun 2013 17:08:15 +0000</pubDate>
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					<guid>http://cycling74.com/forums/topic/jit-dimmap/#post-40515</guid>
					<title><![CDATA[jit.dimmap ?]]></title>
					<link>http://cycling74.com/forums/topic/jit-dimmap/#post-40515</link>
					<pubDate>Sun, 26 Oct 2008 10:12:19 +0000</pubDate>
					<dc:creator>Cheng Chien-Wen</dc:creator>

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						<p>I am trying to learn jit.dimmap, but I do not understand what &#8220;map&#8221; and its parameters do even after having read the reference and help files.</p>
<p>For example, What do &#8220;map 1 0&#8243; and &#8220;map 0 1&#8243; mean ? </p>
<p>Thanks.</p>
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					<guid>http://cycling74.com/forums/topic/jit-dimmap/#post-143443</guid>
					<title><![CDATA[Re: jit.dimmap ?]]></title>
					<link>http://cycling74.com/forums/topic/jit-dimmap/#post-143443</link>
					<pubDate>Thu, 02 Sep 2010 15:15:44 +0000</pubDate>
					<dc:creator>spokeNine</dc:creator>

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						<p>Can anyone answer this person&#8217;s question?<br />
It&#8217;s my question now, too.  Experimenting with a range of possibilities hasn&#8217;t helped.</p>
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					<guid>http://cycling74.com/forums/topic/jit-dimmap/#post-143444</guid>
					<title><![CDATA[Re: jit.dimmap ?]]></title>
					<link>http://cycling74.com/forums/topic/jit-dimmap/#post-143444</link>
					<pubDate>Thu, 02 Sep 2010 15:42:02 +0000</pubDate>
					<dc:creator>Bas van der Graaff</dc:creator>

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						<p>Huh, from the help file this looks pretty obvious to me. Dimmap has 2 params, &#8216;map&#8217; and &#8216;invert&#8217;.</p>
<p>Map is used to map dimensions. So if I have a movie that is x * y pixels in size, &#8216;map 0 1&#8242; will cause it to stay the same (first axis is 0, second axis is 1), while &#8216;map 1 0&#8242; will cause the movie to be mirrored diagonally, and the output will be y * x pixels. Note: maybe you guys tried putting in duplicate dimensions (like &#8216;map 0 0&#8242;)&#8230;you can&#8217;t.</p>
<p>Invert is only used to mirror about orthogonal axis. &#8216;Map 0 1&#8242; and &#8216;invert 1 0&#8242; together will cause the image to be mirrored horizontally (only the first axis is inverted)</p>
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