Cycling 74 » Topic: LCD Question

LCD Question

Nate — Thu, 15 Apr 2010 17:45:07 +0000

Positions in the lcd object are all relative to the upper left corner of the window. As in a lcd with size 100 100, the center is at 50,50. Is there a way to set the positions relative to the center of the window thereby avoiding having to convert to and from different relative positions?

Re: LCD Question

justin — Fri, 16 Apr 2010 13:24:33 +0000

unless i’m mistaken, its just a question of adding an offset to the position message.

so in your case adding 50 to the x and y position will make position 0 0 the centre of your image. adding -50 to both x and y positions will make it go to top left corner…

Re: LCD Question

Nate — Fri, 16 Apr 2010 20:29:24 +0000

Justin, thank you for your response!

you are absolutely correct and I have been doing so.

I am trying to create a patch for my students that graphs a hyperbola in the form of ((x-h)^2)/(a^2))- ((y-k)^2)/(b^2))=1 on the standard xy coordinate plane so the student can “play around” with different values of h, k, a, and b to see how the graph responds.

The patching becomes increasingly complicated when trying to re-size or change the axises intervals so setting the relative position of (0,0) to the center would be helpful but not necessary.

Any suggestions or pointers on graphing functions using Max would be greatly appreciated.

Thanks!

Re: LCD Question

Samuel Freeman — Fri, 23 Apr 2010 16:05:00 +0000

2 thoughts:

in JSUI coordinates there is ‘screen’, where (0,0) is top left same as lcd, and there is ‘world’ where (0., 0.) is the centre and the edges are ±1. for a square stage.

you could get away with only doing the offset once on lcd by recording the hyperbola as a sprite centred at (0,0) and then positioning it to the middle of the lcd when drawing the sprite…

I’d be interested to see what you have already (I’m resisting the urge to implement ((x-h)^2)/(a^2))- ((y-k)^2)/(b^2))=1 )

sdf