azifikare4us

I search a simple a accurate way to create a list as :

- I want to create a new list of m items using only some items of my original list.

I can use zl.slice to extract the items from the original list, but is there a function which create a list from x items and repeat them to have a m items list.

I search a simple a accurate way to create a list as :
- I have an input list of n items
- I want to create a new list of m items using only some items of my original list.

Hope it's clear.
Thank you for your answers.


list-trick

That's very general.. Perhaps this is useful?

Thank you very much, you just confirm that i am on the good way.

Here is the result, may be you have some improvements to make :

I don't understand what you are trying to do here...

Example input.. example output? What kind of steps?

Example input.. example output?  What kind of steps?


- In the second inlet, you send a list (of steps). ex. : 1 2 3 4 5 6 7 8

- In the first inlet, you send the number of steps (or items) of the lists you want to copy (duplicate). ex. : 2

The patcher must create a list as same length as the original list (inlet 2) but containing copied items (steps, inlet 1) of the original list.

So for : (Inlet 1 : 2, Inlet 2 : 1 2 3 4 5 6 7 8

Then the result must be : 1 2 1 2 1 2 1 2

For : (Inlet 1 : 4, Inlet 2 : 1 2 3 4 5 6 7 8

Then the result must be : 1 2 3 4 1 2 3 4

And if the Inlet 1 value is greater or equal to Inlet 2 list length, nothing is made, because it's not usefull.

Ok, here is the patcher spec :
- In the second inlet, you send a list (of steps). ex. : 1 2 3 4 5 6 7 8
- In the first inlet, you send the number of steps (or items) of the lists you want to copy (duplicate). ex. : 2

So for : (Inlet 1 : 2, Inlet 2 : 1 2 3 4 5 6 7 8
Then the result must be : 1 2 1 2 1 2 1 2

For : (Inlet 1 : 4, Inlet 2 : 1 2 3 4 5 6 7 8
Then the result must be : 1 2 3 4 1 2 3 4

Ahh.. I see. Well it looks like you worked it out. Optimization will likely be a function of how you are using it.. Maybe add a modulo object to allow for inlet 1: 3, result: 1 2 3 1 2 3 1 2 etc..

Ahh.. I see.  Well it looks like you worked it out.  Optimization will likely be a function of how you are using it..   Maybe add a modulo object to allow for inlet 1: 3, result:  1 2 3 1 2 3 1 2  etc..


This thread is somewhat related. It might give you some more ideas.. https://cycling74.com/forums/iterate-over-list-n-times/

Thank you for your help, I will take a look at your link.

List trick