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		<title>Cycling 74  &#187;  Topic: use the default inlet of an external</title>
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		<link>http://cycling74.com/forums/topic/use-the-default-inlet-of-an-external/feed</link>
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		<pubDate>Wed, 19 Jun 2013 14:31:52 +0000</pubDate>
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					<guid>http://cycling74.com/forums/topic/use-the-default-inlet-of-an-external/#post-62633</guid>
					<title><![CDATA[use the default inlet of an external]]></title>
					<link>http://cycling74.com/forums/topic/use-the-default-inlet-of-an-external/#post-62633</link>
					<pubDate>Wed, 28 Mar 2012 08:36:40 +0000</pubDate>
					<dc:creator>freepoulite</dc:creator>

					<description>
						<![CDATA[
						<p>Hello everybody,</p>
<p>Since a few days, I&#8217;m learning how to build external in C<br />
but i can&#8217;t figure out how can i use the inlet 0 ( default)<br />
I&#8217;ve tried to add </p>
<p>void simplemax_in0(t_simplemax *x,long n); //prototype</p>
<p>and</p>
<p>void simplemax_in0(t_simplemax *x,long n){<br />
    post(&#8220;hello world! );<br />
}</p>
<p>but the inlet 0 don&#8217;t understand int ( max window message)</p>
<p>How can i use it?</p>
<p>thanks</p>
						]]>
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				<item>
					<guid>http://cycling74.com/forums/topic/use-the-default-inlet-of-an-external/#post-226226</guid>
					<title><![CDATA[Re: use the default inlet of an external]]></title>
					<link>http://cycling74.com/forums/topic/use-the-default-inlet-of-an-external/#post-226226</link>
					<pubDate>Wed, 28 Mar 2012 15:32:59 +0000</pubDate>
					<dc:creator>nicolas danet</dc:creator>

					<description>
						<![CDATA[
						<p>Hello,</p>
<p>you should read the SDK again ;-)</p>
						]]>
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				<item>
					<guid>http://cycling74.com/forums/topic/use-the-default-inlet-of-an-external/#post-226227</guid>
					<title><![CDATA[Re: use the default inlet of an external]]></title>
					<link>http://cycling74.com/forums/topic/use-the-default-inlet-of-an-external/#post-226227</link>
					<pubDate>Thu, 29 Mar 2012 05:41:12 +0000</pubDate>
					<dc:creator>freepoulite</dc:creator>

					<description>
						<![CDATA[
						<p>Good advice :) &#8230; i&#8217;ve find it</p>
<p>thank you Vanille</p>
						]]>
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