gpvillamil

I'm using a little bpatcher to enter hh:mm:ss intervals, and I'm using regexp to break out everything between the :

However, I'd like for the last entry, the seconds, to allow for floating point entry, ie. enter 00:00:01.5 for one and half seconds.

Can't seem to get it to work, the regexp ignores everything after the .

What can I do? Do I need to include the "." as a delimiter within the regexp? What will that do if I *don't* include the decimal fraction?

using-regexp-to-parse-out-floating-point-numbers

Awesome, thanks! That seems to work perfectly. Perl regexp are somewhat out of my league...