If I am using groove to do time stretching, and the original buffer length is 2000ms and the groove (sig~) speed is 1, then the groove plays for 2000ms.

What is the math for changing groove speed (sig~) to .5 = 4000ms, or 2 = 1000ms, or -2.5 = 8000ms etc. ?

Using float to change the groove (sig~) speed.

I need to send this new time length to a second buffer so I can copy/record the first buffer to it after stretching the time.

Using float to change the groove (sig~) speed. 

Hi,
This is probably something simple.
If I am using groove to do time stretching, and the original buffer length is 2000ms and the groove (

exponential-time-decreaseincrease

(yes, that is the same as lenght/playspeed, but i gave that answer for a reason.)

(1 / playspeed) * length

[!/ 1.]
[* 2000.]

(yes, that is the same as lenght/playspeed, but i gave that answer for a reason.)


Exponential time decrease/increase