Brian H.

I need something fairly simple here: I want to take a long list and break it into separate lists of exactly 2 items.

A job for [zl.iter]– Seems straight enough. But apparently, when the input list has fewer items than its argument, it still passes them (!). So, when I want lists of 2 items from [zl.iter] and send it a list of 9 items, I get 4 lists of 2, and then also the remaining odd item. Seems like it makes it less useful than it could be.

That odd number could just be discarded or, ideally, sent to another outlet. I tried [zl.slice], but it basically has the same problem.

Before I have to get into it further with [zl.len] comparisons, etc., is there not a better way to do this? As I am constantly saying about Max, "seems like this should be easy..." 

Hi,
I need something fairly simple here:  I want to take a long list and break it into separate lists of exactly 2 items.

A job for [zl.iter]– Seems straight enough.  But apparently, when the input list has fewer items than its argument, it still passes them (!).  So, when I want lists of 2 items from [zl.iter] and send it a list of 9 items, I get 4 lists of 2, and then also the remaining odd item.  Seems like it makes it less useful than it could be.

That odd number could just be discarded or, ideally, sent to another outlet.  I tried [zl.slice], but it basically has the same problem.

Before I have to get into it further with [zl.len] comparisons, etc., is there not a better way to do this?  As I am constantly saying about Max, "seems like this should be easy..." 

Thanks,
Brian

Hi,
I need something fairly simple here:  I want to take a long list and break it into separate lists of exactly 2 items.
A job for [zl.iter

list-groups-of-2

Doubleug has the most straightforward approach, but if you need to have the remainder numbers, using zl.len with gate should be easy. Here's a configurable solution you could reuse as an abstraction:

List groups of 2?