Sama Akira

[a, a2, a3, ......]; [s1, s2, s3...]; [1, 2, 3, 4, 7....] ....

I need the rearrangement of the elements of one array also occur with another array. 

[a2, a, a3...] =>[s2, s, s3...] => [2, 1, 3, 4, 7....]

What's the easiest way to do this? So as not to duplicate the same code for all arrays.

Some very noob question . 
I have multiple arrays. For example 
[a, a2, a3, ......]; [s1, s2, s3...]; [1, 2, 3, 4, 7....] ....
 I need the rearrangement of the elements of one array  also occur with another array. 
[a2, a, a3...] =>[s2, s, s3...] => [2, 1, 3, 4, 7....]

What's the easiest way to do this? So as not to duplicate the same code for all arrays.
Thanx. 

Some very noob question . 
I have multiple arrays. For example 
[a, a2, a3, ......]; [s1, s2, s3...]; [1, 2, 3, 4, 7....] ....
 I need the r

permutation-of-elements-of-several-arrays-at-the-same-time

Do you mean, which elements occur in both arrays? If so, you might use this.

array3 = array1.filter(function(x) {return array2.indexOf(x) >= 0;} );

Oh no. Sorry for my bad question formulation

I mean - When I swap the elements of one array, the elements also change in other arrays.

Oh no. Sorry for my bad question formulation
I mean - When I swap the elements of one array, the elements also change in other arrays.

Ah, okay. Then you want to copy the arrays so they can stay independent. If the array is flat (meaning none of the elements are arrays), you can accomplish this with arrayCopy = arrayOriginal.slice(). Then changing arrayCopy doesn't change arrayOriginal, or vice versa.

If the array has other arrays inside it, you can do arrayCopy = JSON.parse(JSON.stringify(arrayOriginal)); however, that will change all "undefined" into "null," along with a few other side effects.

Unless you meant you want the elements to change, and they don't already. But I assume you mean they do change in others, but you don't want that.

permutation of elements of several arrays at the same time