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### differenciating trigonometric function with delta~

Feb 01 2008 | 5:42 pm

Hi list,

I was confused by the use of delta~ :
wanted to differentiate a cosine to get a sine~.
I thought i would need to multiply the output of delta
by 44100 to approximate derivative by finite difference..
but found out I had to multiply by some 6900 or so to
get the amplitude of my sine wave to have unit amplitude…
Am I blind about something ?

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#P comment 141 251 82 9109513 The sine (*-1);
#P comment 431 262 59 9109513 The cosine;
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135 135 0;
#P newex 260 341 27 9109513 +~;
#P newex 302 299 27 9109513 *~;
#P newex 260 297 27 9109513 *~;
#P newex 260 258 40 9109513 *~ 4410;
#P newex 260 229 33 9109513 delta~;
#P newex 261 171 70 9109513 *~ 6.283186;
#P newex 261 195 35 9109513 cosx~;
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Feb 02 2008 | 10:59 am

Vincent Goudard schrieb:
> Hi list,
>
> I was confused by the use of delta~ :
> wanted to differentiate a cosine to get a sine~.
> I thought i would need to multiply the output of delta
> by 44100 to approximate derivative by finite difference..
> but found out I had to multiply by some 6900 or so to
> get the amplitude of my sine wave to have unit amplitude…
> Am I blind about something ?

If you change the frequency, you’ll see that the normalisation value is
dependent on that. delta~ will output a maximum value at the zero
crossing. its the difference between adjacent samples. That difference
is dependent on the sampling rate and frequency of the sine. You would
have to calculate your normalisation value according to this…

You’ll see, that your assumed value of 4410 will fit for the frequency
of pi/2 (1.570796 Hz)

Hope this helps…

Stefan

Stefan Tiedje————x——-
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