I don't understand how *0.2-0.1 can set the cell to -0.10 if it is 0.

For me *0.2-0.1=0.1, so I suppose I don't correctly read the expression.

I don't understand how *0.2-0.1 can set the cell to -0.10 if it is 0.
For me *0.2-0.1=0.1, so I suppose I don't correctly read the expression.
Could someone lend a hand?

expr-cell04-0-cell04-3-0-2-0-1

On 8 sept. 08, at 11:27, Derrick Giscloux wrote:

> I don't understand how *0.2-0.1 can set the cell to -0.10 if it is 0.

> For me *0.2-0.1=0.1, so I suppose I don't correctly read the 

multiplication have higher precedence over the addition:

0 (the result of 0 * 0.2) minus 0.1 gives -0.1

> Hello,
>
> I don't understand how *0.2-0.1 can set the cell to -0.10 if it is 0.
> For me *0.2-0.1=0.1, so I suppose I don't correctly read the  
> expression.
> Could someone lend a hand?

I'm trying now to set a value in cells 1&2 and the inverse of this value in cells 0&3.

@expr "(cell[0]%4.>0.)*(cell[0]%4.<3.)*0.2-0.1"

@expr "(cell[0]%4.>0.)(cell[0]%4.<3.)0.2-0.1"