Anthony Palomba

I am trying to process the lines of a file using "readline". 

I have pasted my code below. For some reason when I call

the method string "search", I get the following error...

• error: js: (null): Javascript SyntaxError: unterminated character class , line 0

• error: js: error calling function Test

For the life of me, I can not figure this one out. I know

search is a method that exists because I have called 

it before with no problems. Anyone have any ideas?

    IniFile = new File(filename, "read");

        post("FileIO Error: could not open file.n");

        post("file open.n");    

    post("IniFile.position = " + IniFile.position + "n");

    post("IniFile.eof = " + IniFile.eof + "n");

    while(IniFile.position != IniFile.eof)

        Line = IniFile.readline (256);

        post("input: " + Line + "n");

        Result = Line.search("[");

            // remove section delimiters.

            Line.replace("[", "");

            Line.replace("]", "");

            OutputStr += Line + " ";

I am trying to process the lines of a file using "readline". 
I have pasted my code below. For some reason when I call
the method string "search", I get the following error...

• error: js: (null): Javascript SyntaxError: unterminated character class , line 0
• error: js: error calling function Test

For the life of me, I can not figure this one out. I know
search is a method that exists because I have called 
it before with no problems. Anyone have any ideas?

// inlets and outlets
inlets = 1;
outlets = 1;

var 	IniFile = null; 
function Test(filename)
{
	if(IniFile != null)
	{
		IniFile.close();
		IniFile = null;
	}

	IniFile = new File(filename, "read");
	if(IniFile.isopen == false)
	{
		post("FileIO Error: could not open file.n");
		return;
	}
	else
		post("file open.n");	

	var OutputStr = "";
	IniFile.position = 0;
	post("IniFile.position = " + IniFile.position + "n");
	post("IniFile.eof = " + IniFile.eof + "n");
	var Result = 0;
	var Line = "";
	while(IniFile.position != IniFile.eof)
	{
		Line = IniFile.readline (256);
		post("input: " + Line + "n");
		Result = Line.search("[");
		post("search done...n");
		if(Result != -1)
		{
			// remove section delimiters.
			Line.replace("[", "");
			Line.replace("]", "");
			OutputStr += Line + " ";
		}	
	}

string-search-problem

On 23-janv.-08, at 20:48, Anthony Palomba wrote:

> For the life of me, I can not figure this one out. I know

> search is a method that exists because I have called

> it before with no problems. Anyone have any ideas?

I can't test your code now, but afaik, String.search() expects a 

regular expression as argument, but "[" doesn't look like a RE.

Centre de Recherches et de Formation Musicales de Wallonie

> For the life of me, I can not figure this one out. I know
> search is a method that exists because I have called
> it before with no problems. Anyone have any ideas?

I can't test your code now, but afaik, String.search() expects a 
regular expression as argument, but "[" doesn't look like a RE.

_____________________________
Patrick Delges

Centre de Recherches et de Formation Musicales de Wallonie
http://www.crfmw.be/max


String.search takes a string and searches it for a 

specified substring. It returns -1 or the index of the 

beginning of that substring. I am pretty sure this works.

One difference is that when I normally use it, I pass 

a string in from outside. In this case I am using fileobject.getline.

String.search takes a string and searches it for a 
specified substring. It returns -1 or the index of the 
beginning of that substring. I am pretty sure this works.

One difference is that when I normally use it, I pass 
a string in from outside. In this case I am using fileobject.getline.


On 24 janv. 08, at 00:45, Anthony Palomba wrote:

> String.search takes a string and searches it for a

> specified substring. It returns -1 or the index of the

> beginning of that substring. I am pretty sure this works.

I use it in ej.function, and it works fine.

> String.search takes a string and searches it for a
> specified substring. It returns -1 or the index of the
> beginning of that substring. I am pretty sure this works.

On Jan 23, 2008, at 3:45 PM, Anthony Palomba wrote:

Your error message would suggest it thinks "[" is the beginning of a 

regexp charset. So for ordinary strings maybe this is true since they 

are the same as their representation as a regular expression.

Try using "[" and "]" --i.e. backslash to escape the brackets...

>
> String.search takes a string and searches it for a
> specified substring. It returns -1 or the index of the
> beginning of that substring. I am pretty sure this works.

Your error message would suggest it thinks "[" is the beginning of a  
regexp charset. So for ordinary strings maybe this is true since they  
are the same as their representation as a regular expression.

Core_JavaScript_1.5_Reference:Objects:String:search

It is a regular expression. So you definitely need to escape brackets 

http://developer.mozilla.org/en/docs/ 
Core_JavaScript_1.5_Reference:Objects:String:search

It is a regular expression. So you definitely need to escape brackets  
and the like.

http://www.w3schools.com/jsref/jsref_search.asp

I was referencing this...
http://www.w3schools.com/jsref/jsref_search.asp

On Jan 23, 2008, at 4:02 PM, Anthony Palomba wrote:

Well it would appear that this isn't the way it works in JS 1.5 (may 

have been the case in previous versions, or they may be glossing over 

regexp behavior). Core Javascript book and mozilla site I sent in my 

>
> I was referencing this...
> http://www.w3schools.com/jsref/jsref_search.asp
>
> Is this a bad source?

Well it would appear that this isn't the way it works in JS 1.5 (may  
have been the case in previous versions, or they may be glossing over  
regexp behavior). Core Javascript book and mozilla site I sent in my  
last message are highly recommended

I went ahead and treated it as a regular expression. Line.search("[/[]") does the trick. Thanks for helping

I went ahead and treated it as a regular expression. Line.search("[/[]") does the trick. Thanks for helping
me track this one down.


String.search problem...