How to get the current directory


    Jun 28 2007 | 4:29 pm
    Hello Everyone,
    I need to get somehow the directory where the current patcher (the one containing my mxj object) is stored (I have an xml with default settings for my object, and I would like to place this in the same directory as the Max patch itself). Using System.getProperty("user.dir"), I get the root folder of my filesystem (I'm on OS X 10.4.10) if executed from mxj, while in Eclipse I get the current runtime folder (as expected). Is there some mxj-specific solution for this? Also, is there any mxj method to get the current Max/MSP installation path?
    Thank you, Adam
    ________________ Siska Ádám +36 (70) 207-63-85 http://apocalypse.rulez.org/~sadam

    • Jun 28 2007 | 6:36 pm
    • Jun 10 2011 | 1:25 pm
      a "filepath" object with "default" argument
    • Jun 14 2011 | 9:03 am
      The previews one don't work. This seems to be the way
    • Jan 20 2012 | 8:40 am
      Thanks sandoval31 - one of the things I was looking for!
    • Oct 16 2012 | 3:33 pm
      This is too late to be useful to the OP, but I think the answer he/she wanted was something along these lines (untested).
      public class MyMaxObject extends MaxObject{
      
        public MyMaxObject(){
          String mainPatcherPath = this.getParentPatcher().getFilePath();
          post(mainPatcherPath); // prints the location of the patcher containing the mxj object
        }
      }