If you just want a rotating fixed picture for your dial, you might as well use pictctl (I think it's a lot cheaper in terms of cpu usage too). You could also draw something in js, capture it to an image and rotate that. Or load a texture into js, as opposed to pictctl. There is an example that should get you started, called "jsui_imagestuff-example.pat". Pictctl is by far the easiest option though.

To me it doesn't make much sense to calculate and draw a new dial on every rotation if it's not changing its appearance along the way. You'll be wasting your precious cpu cycles;-)

Best, Thijs

Thanks for your reply,

That's a valid point about the CPU - the only other problem is that I am a PC user and have no pict file editor. Also creating all the different pict files will be time consuming - I am on a strict time scale, this will be a submission for an MIT degree in a month, so the less time I have to spend getting the solution the better. Some of the other JSUI dials simply rotate so I would have hoped there was a simple tweak I can make to the code of 3ddial to make it perform like this. - Anyone?

ok here's your tweak: i just commented out the drawing commands you don't want:

/*j

> > I would have hoped there was a simple tweak I can make to the code > of 3ddial to make it perform like this.

default: // 3d sphere with (sketch) { glenable("depth_test"); shapeslice(40,10); glcullface("back"); // wireframe on/off if (vwire) { glpolygonmode("front","line"); glpolygonmode("back","line"); } else { glpolygonmode("front","fill"); glpolygonmode("back","fill"); } // erase background glclearcolor(vbrgb); glclear(); // fill bg sphere glcolor(vrgb2); moveto(0,0,0); sphere(0.8,0,360,0,90); // fill fg arc glclear("depth"); glcolor(vfrgb); /* sphere(0.8,-90-val*360,-90,0,90); // draw arc outline gldisable("depth_test"); glenable("line_smooth"); shapeslice(80,1); glcolor(0,0,0,1); framecircle(0.8,-90-val*360,-90); */ glcolor(0,0,0,1); moveto(0,0); /* lineto(0,-0.8); moveto(0,0); */ theta = (0.75-val)*2*Math.PI; lineto(0.8*Math.cos(theta),0.8*Math.sin(theta));