Calculating total delay of tapin/tapout series?
Hi-
An elementary question, but I'd appreciate a reality check from someone. How to calculate the total delay in a series of [tapin]/[tapout] objects.
[tapin]/[tapout] will delay a signal in increments smaller than vector size, correct?
Let's say I have a vector size of 512 samples, or roughly 11ms.
I want to delay a signal by 5ms in each of two [tapin]/[tapout]s.
So: is total delay 10ms (ie 5ms + 5ms)?
...or is it 21ms (ie 5ms + 11ms + 5ms)?
Thanks, Charles
no, tapin~/tapout~ don't allow for delay times smaller than the vector size. you have to use delay~ or comb~ for that.
aa
Well that answers that! Don't know where I got the idea that they would.
Thanks again, Charles
On second thought, are you sure you're correct? I just made this test, and with the vector size set at 512 samples, the resulting audio file shows two clicks spaced 5ms apart:
Oops! You're right. When the vector size is 64 samples it's 5ms apart, but when it's 512, the delay looks like about 11ms...