[poly~] second argument denotes the number of instances (voices)

#n can be used inside your abstraction for argument variables - see topics and tutorials "$ and #"

it takes all of us LoneMonad http://faculty.roosevelt.edu/malone/downloads.htm

Thanks for your reply. #n works in abstractions but it doesn't seem to work inside poly~. I tried the following:

Save as insidepoly:

Then try this:

The t inside the poly~ detected zero's as arguments. Did I overlook something obvious?

Thanks, Mattijs

Try

[poly~ 1 args 1 2 3]

instead.

The gory details of poly~'s arguments can be found in the "optional-arguments" subpatch of poly~'s help file.

hth, Owen

i control variables of abstractions inside [poly~] with send/receive or send~/receive~

it takes all of us LoneMonad http://faculty.roosevelt.edu/malone/downloads.htm

Thanks Owen,

That works. Pity though that now I have to do [poly~ grain~ 16 args 16], where the 16's are always the same, but I can live with that.

> i control variables of abstractions inside [poly~] with send/receive or send~/receive~

Yeah, me too normally, but I wanted this to be a black box where it would be enough to set the amount of voices. The grain patcher inside needs its phase to be set according to the amount of voices.

Anyway, thanks guys, this will do fine. Mattijs

you could have a loadbang in each voice send a bang via a send/receive connex. since the send/receive pair could be like a global variable. each voice would bang a counter and that would tell you how many voices you have.

there have got to be > 1*10^999 ways to get info on the state of your poly~ abstractions...

the args way mightbe the easiest, but if you need a dynamic way of dealing with the number of voices you could use thispoly~ and its mute state to allow the number of *active* voices to be known too...

also you could probably come up with a phase setting scheme that was independent of total voice count. for example use a hashtable where the voice number from thispoly~ would call a phase value. 1, 0 2, 180 3, 90 4, 45 5, 135 6, 22.5 7, 67.5 8, 112.5 9, 157.5 10, (keep splitting the differnce)

you are propably right. The best way though would be if thispoly~ would simply output the total voice amount on bang.

Cheers, Mattijs