Freeing/clearing a dictionary without causing memory leaks

    Apr 17 2012 | 4:32 pm
    Hi folks,
    I have a scenario that makes me unsure about whether I am leaking memory or not. Here's the (simplified) code snippet in question:
    t_dictionary *d;
    t_dictionary *sd;
    t_atom argv[64];
    long argc = 64;
    long i;
    d = dictionary_new();
    if (d) {
        for (i = 0; i < argc; i++) {
            sd = dictionary_new();
            if (sd) {
                dictionary_appendlong(sd, gensym("data"), 74);
            atom_setobj(argv + i, sd);
        dictionary_appendatoms(d, gensym("subdictionary_list"), argc, argv);
        // do more stuff with the dictionary
        // and finally call...
    Now, when calling dictionary_clear() will all my subdictionaries be automatically freed ?
    The reason I am asking is that I know that when appending atoms to a dictionary the atoms will be converted to an t_atomarray. So I basically have an t_atomarray of object pointers appended to my main dictionary. When clearing (or freeing?) an t_atomarray the API docs say that "(it) does not perform a 'deep' free, meaning that any #A_OBJ atoms will not have their object's freed. Only the references to those objects contained in the atomarray will be freed."
    Hence I am unsure whether I have to manually free all subdictionaries or whether dictionary_clear() will automatically take care of that for me.
    Thanks for any clarification.
    - Luigi

    • Apr 17 2012 | 4:36 pm
      If the atomarray contains objects, they will be auto-freed with the dictionary (dictionary_appendatoms enables the "deep free" behavior of the atomarray in this case).
    • Apr 17 2012 | 4:46 pm
      Great, that's exactly what I needed to know. Thanks Jeremy!
      - Luigi