log in vexpr

MaxMSP
phiol's icon

phiol

Hi all,

I'm try to do a log on a list but can figure out how to do it using vexpr log10

so I resorted to jit.op @op log @val 64

Could anyone shed light to how to do with vexpr instead
thanks

phiol

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kLSDiz's icon

kLSDiz

The simplest solution works for me:

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But if you want to calculate a logarithm to a arbitrary base (jit.op @op log is just a natural logarithm) you can use this formula: log(x)/log(base).
(see https://en.wikipedia.org/wiki/Logarithm#Change_of_base)

phiol's icon

phiol

Thanks a lot KLSDIZ

All I need to know (or at least this is what I understand) is that log is a function and so it needs the () as in log()

so vexpr log($f1)/log(64) + 1. or vexpr log($f1)/log($f2) + 1 would give me the dynamic base.

Thanks

phiol's icon

phiol

what I actually wanted was a booster in both directions
not even a log.

here it is

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