## Logarithmic scaling from input range

Oct 14 2014 | 4:31 pm
hi everyone,
I am in the middle of a math problem. I assume that could be resolved by applying logarithmic scaling, but that's beyond my max knowledge,
Let say you have an input range of data from -50 to 50 sent in osc from a horizontal slider (0 in the middle). I want to scale the output, in order to still have a range from -50 to 50, but with a scale of data more precise as you get closer to 0 (from either ways, negative, or positive)
thanks for the help! eric

• Oct 14 2014 | 5:19 pm
Hi I'm AFK at the moment, but search here for "tweening" or "easing functions". Essentially all you need to do is scale your input to between 0.0 and 1.0, then apply your curve using a power, either > or < 1.0 then scale back up to your desired output range.
Brendan
• Oct 14 2014 | 5:37 pm
and, here, for more comprehensive practical detail (from Gregory Taylor, mwah!)
• Oct 14 2014 | 5:41 pm
This depicts it a little better:
(from that other thread, but look at Gregory's equations too)
• Oct 14 2014 | 5:52 pm
thx brendan,
..apparently, there's something i was looking for, the so called 'split range'
will dig that! thx!
• Oct 14 2014 | 6:37 pm
thx again brendan, but i tried your two patches, but i can't get the average data correctly. I mean, for instance on a scale -50 to 50, if i have 0 in input, i must found back this on output. Only datas around the 0 are progressively scaled . ..and i don't get that with this patches,...
any suggestion?
• Oct 14 2014 | 8:06 pm
Hi Are you asking for linear input/output between -50 and -10 (for example), then greater resolution (a curve) between -10 and 0?
• Oct 14 2014 | 8:21 pm
are you looking for something like this?
sorry for the hacky patch, you get the idea.
• Oct 14 2014 | 8:32 pm
yes that was that! :)
thx a lot!