not understanding max's log computation


    Sep 16 2009 | 2:23 am
    Hi,
    I'm trying to use [scale] to output logarithmically, but can't really understand how it is calculating its output. If the exponential base value is very close to 1 (e.g. 1.005) the first number output is much higher than 0.
    Maybe it's a lack of understanding of maths on my part, but it seems to me as though the curve should still be starting at 0, even if it looked almost exactly like a straight line, then as the exponent gets higher the curve would develop and show itself more drastically.
    So... why the big jump at 0? And what can I do to get a good scalable logarithmic curve?
    Jay

    • Sep 16 2009 | 6:36 am
      There's a common understanding among max users that scale is not suitable for logarithmic scaling. It doesn't work. (As long as you ignore it's fifth argument, it's a fantastic object.) One of the ways of dealing with this is:
      _ johan
    • Sep 16 2009 | 8:25 pm
      Also, check out the awesome (and free!) Litter Power Starter Pack:
      The lp.scampf object has log/expo scaling which works perfectly!
    • Sep 16 2009 | 11:34 pm
      thanks for these suggestions...
      i guess i should say is that i'm trying to program dials which can be logarithmically controlled, to a user-defined degree (where 1 = linear). any suggestion?
    • Sep 17 2009 | 7:49 am
      The example I posted before is exactly about this. The number 1 creates a straight line (that is a number very close to 1 like 1.000001). As this number grows, the curvature increases.
      _ johan
    • Sep 17 2009 | 12:27 pm
      thanks, yeah after messing around with it for a while i figured that out!