quick question - jit.expr not giving me a third inlet


    Feb 17 2014 | 5:00 am
    Hi, I am playing around with jit.expr to understand some of its functionality from an intuitive level. I made this patch to play with jit.multiple. I imagine that if I use in[0], in[1], and in[2] as variables, I should have a third inlet, as I'm referencing that inlet through in[2]. However, my jit.expr object still only has two inlets. Here is my example patch:
    Thanks for your help!

    • Feb 17 2014 | 5:46 am
      put @inputs 3 in your jit.expr object
      look at the helpfile and you will see an example of how @inputs can be used to specify how many inputs you want to have. this will make them appear
    • Feb 17 2014 | 3:11 pm
      great, thx!