random probability

The solution depends on what kind of distribution you want of course, but a simple way in Max would be something like this:

I.e. you start with a list containing all possible numbers, with number repeated more often if you want them to appear more often. For example, if you filled the list with 100 numbers, 80 of them being a "2", then you'd get a "2" 80% of the times of banging that list.

But here's a somewhat more elegant method in javascript:

function bang()
{
var weights = [0.005, 0.05, 0.8, 0.05, 0.02, 0.02, 0.02, 0.02, 0.01, 0.005];
var weightsum = 0;
var randvar = Math.random(); // A random number between 0 and 1

for (i = 0; i
{
if (randvar>weightsum && randvar
{outlet(0, i);return true;}
else
{weightsum += weights[i];}
}
}

P.S. The "weights" array contains the chances of getting each number from 0 to 9, in this case. Here, you'd get "0", with the probability of 0.005, "1" with the probability of 0.05, "2" with the probability of 0.8, etc.

The numbers in this list must always add up to 1. The number of elements in the list determines the range of random numbers it outputs. It gives random numbers between 0 and the number of items in the list - 1.