regexp multiple substitutions?

    Jan 29 2013 | 11:56 pm
    basically combining this into one. this seems wasteful
    it also doesn't work as I want it to.

    • Jan 30 2013 | 12:23 pm
      this is highly frustrating... Does ANYONE know how can I do that?
      I just want this: detect Item1 Item2 Item3 >>> replace Item1 with X; replace Item2 with Z, replace item3 with Y.
      I don't want to break-up the list
    • Jan 30 2013 | 2:12 pm
      If the items are consecutive you can do it like this.
    • Jan 30 2013 | 3:04 pm
      I have a variable list size, so brute force isn't feasible.
      I just thought since regular expression in perl/java does allow multiple substitutions that there is a way to do it in max.
      edit: theres a problem this way,
      if the input is all x's, the output wont go through the next regexp. Actually if there is anything but all characters present then it wont go through.
    • Jan 30 2013 | 3:31 pm
      I actually had all the outlets connected and it didn't occur to me to connect the "no match" to the next input. I need my head checked.
      Thanks a lot for your help!
    • Jan 30 2013 | 4:33 pm
      Are you sure you need regexp for that? A simple coll can do the trick
    • Jan 30 2013 | 11:32 pm
      My first attempt was with iter, with triggers instead of coll though. For lists i feel regexp to be cleaner.
      Where'd you get 6.1??
    • Jan 31 2013 | 1:54 pm
      IMHO regexp is for "withing string manipulation", here you just need to replace items in a list.
      for the second question... that's a secret ;-)
    • Jan 31 2013 | 7:13 pm
      True, i just for some reason try to avoid breaking up lists with iter and recombining them. I feel like it could fall out of sync - i know its completely stupid and I'm just paranoid, but still. :)
      I want to be a beta tester too :) let me in!
    • Feb 02 2013 | 11:11 am
      Ah, okay. I'll go with triggers then :)