Nov 20 2011 | 11:52 pm

There are two posts discussing the formula for the scale object, but none really answer the question posted.

If the formula from the reference is:

y = b e-a log c ex log c

Where:

y = result

x = number to scale

a,b,c = the "three typed in arguments"

e = base of the natural log

My question:

There are 4 mandatory arguments, 5 with exponential scaling (which is why I'm interested in the formula). Given only three (a,b,c) - how does this work?

Also, what are the operators in the formula? I'm guessing:

y = b * (e-a) * log(c) * ln(x) * log(c)

Anyone dug in deep enough into their own scaling object?