There are two posts discussing the formula for the scale object, but none really answer the question posted.
If the formula from the reference is:
y = b e-a log c ex log c
y = result
x = number to scale
a,b,c = the "three typed in arguments"
e = base of the natural log
There are 4 mandatory arguments, 5 with exponential scaling (which is why I'm interested in the formula). Given only three (a,b,c) - how does this work?
Also, what are the operators in the formula? I'm guessing:
y = b * (e-a) * log(c) * ln(x) * log(c)
Anyone dug in deep enough into their own scaling object?