sharing: golden ratio

    willum070
    Feb 25 2012 | 8:53 am
    Hi all, I have been messing around with the golden ratio. Don't worry, I didn't change it or anything! Anyhow I have a nice little bit of code that takes a number, and returns the large and small golden proportions of that number. I created it for another patch I am working on, and thought perhaps someone else would find it handy. Cheers!
    • sterlingcrispin@gmail.com
      Feb 27 2012 | 2:54 am
      simple but thank you!
    • Gregory Taylor
      Feb 27 2012 | 5:33 am
      Since phi is the only number that is its own reciprocal, a string of [!/ 1.0] objects will set you up jes' fine....
    • big_pause
      Feb 27 2012 | 1:32 pm
      pedant time
      φ = 1/φ + 1
      i.e. it's not its own reciprocal.
      you may be thinking of Φ = 1/φ (note the case)
      where Φ = φ - 1 (obvious from above and roughly 0.61803)
      a side note,
      2 numbers that are their own reciprocals are 1 and -1
    • Gregory Taylor
      Feb 27 2012 | 2:05 pm
      You're right, of course. I should never post after getting home from the radio station. D'oh!
    • big_pause
      Feb 27 2012 | 3:49 pm
      having a look at the op's patch tho' - this wont work for negative numbers, it's probably easier just setting the larger portion to
      x*Φ
      and the smaller portion to
      x*Φ^2
      Φ=0.618034.... in both cases there
      end of pedant mode :)