std library use in C++ external (eg std::string and std::stoull)


    Jul 04 2013 | 12:55 am
    Hi,
    for synchronisation, I need to send an unsigned long long to my external. I currently compile as .cpp (which works fine if you simply cast the object as a (t_object*))
    however, although I can get the unsigned lon long into the object (as a message)
    I can;t seem to convert it to unsigned long long using std::stoull
    and std::string also gives problems
    why is that? how could the standard library added/used?
    or is tehre a workaround?
    void synchroniser_offset(t_synchroniser *x, t_symbol *s, long argc, t_atom *argv)
    {
    long i;
    t_atom *ap;
    post("message selector is %s",s->s_name);
    //here s->s_name is the value I'm interested in converting to unsigned long long
    ...
    }
    Thanks!

    • Jul 04 2013 | 1:07 am
      okay, so I seem to have got somewhere using;
      #include
      and
      post("message selector is %s",s->s_name);
      unsigned long long ul = strtoull (s->s_name, NULL, 0);
      post("unsigned %llu ", ul);
      perhaps it's using the C version of the standard library?
      being careful to use C-string types, not std::string s?
      but the code above works. Any comments appreciated though so I understand why the issue arose.
    • May 21 2015 | 1:06 pm
      more of a postscipt here, in case anyone comes across this, you cast to a t_class not a t_object to use cpp within max external:
      t_myobject *x = (t_myobject *)object_alloc((t_class*)myobject_class)
      and the external is [myobject]
    • May 27 2015 | 11:02 pm
      You are creating an instance of your class. It can be cast as a t_myobject or a t_object if you want because the first item in your t_myobject struct is a t_object *.
    • May 27 2015 | 11:24 pm
      thanks Emmanuel.
      how about the (t_class*) part of the above?
      that's how I tend to use a cpp extension and have C++ classes included in the external. My last comment is just trying to provide the correct information on doing that.