Delay confusion
Why does this produce no output?
If I cannot use delay this way, what are my other options?
Many thanks in advance
Joe
if del receives a new bang before the old was sent out, the old is forgotten... so in your example it bangs only one time...
pipe behaves different (but if you use it with uzi, the bangs are send out immediately following each other, so pipe also "delays" them in a way that they are sent out immediately following each other).
you could use a combination of metro / counter instead...
tobias
Your solution seems to work (will take another look later) but you explanation seems to imply that there should be one output rather than no outputs (as is the case) - did I misunderstand, or is there another explanation?
Thanks again
Joe
actually, there is one output - if you bang 64 times you will see - or if you connect a print-object: