Roman Thilenius

as usual, the the simple problems turn out to be the most difficult part.

how can i find the coordinates of the corners of a hexagon with a given radius, for example to draw one into a jit.lcd?

i know how to calculate between the inner and outer circle and a hexagon, but i would like to find the corners in an X/Y manner, when the size of the hexagon is given (i use multiples of 13/15 for inner and outer radius, as i want to work with integer numbers of course)

finding-coordinates-of-hexagon

[cos] and [sin] will get you there. Just iterate through the unit circle in steps of pi/3 and you'll have the coordinates of the unit circle, so you can multiply those by r and add the center coordinates. I tried to check if it would be easy to get there so here is my attempt, albeit kinda messy, but you get the picture. Have fun,

until now i tried to avoid calculating circles and went the way over the triangles and rects when constructing the hex.

thats why i first missed that it is THREE values i have to check for beeing close to the next integer and not only two. i thought i am fine with the side length and in outer circle. :) and missed that i also need the height of the damned thing, (which is is √3*a)

well, i guess a bit of unaccuracy will be ok for sizes over 15 pixels. ;/

you are right, it seems to be easier to find the points of the circle by dividing the outline /6, then manually decide which dimension i like.

finding coordinates of hexagon