Peter Nyboer

yet another question about how to articulate something in javascript...

how do I put multiple operations in an op.?

input.op(["!pass","pass","pass","pass"],outmatrix);

(where input and outmatrix are properly defined, and both the same dim/planecount etc.)

This doesn't provide me with the expected results. Is there another trick I'm missing?

yet another question about how to articulate something in javascript...
how do I put multiple operations in an op.?
I would expect the equivalent of 
jit.op @op !pass pass pass pass
would be
input.op(["!pass","pass","pass","pass"],outmatrix);
(where input and outmatrix are properly defined, and both the same dim/planecount etc.)
This doesn't provide me with the expected results.  Is there another trick I'm missing?

multiple-ops-in-jitter-javascript

Hmmm...thanks for the reply. I wouldn't expect it to..."jit.op" isn't initialized like that. To use jit.op in the context of js, you use op as a method on a matrix. For example, the js equivalent of [jit.op @op *] is below. 

I need a way of expressing per-plane operations in the op method, and putting it operations in an array (e.g. "in1matrix.op(["pass","*","pass","pass"],in2matrix);") doesn't work.

var in1matrix = new JitterMatrix(1,"char",320,240);

var in2matrix = new JitterMatrix(1,"char",320,240);

        var input2 = new JitterMatrix(inname);

        in2matrix.frommatrix(input2);

        //outlet(0,"jit_matrix",input2.name);

        var input1 = new JitterMatrix(inname);

        in1matrix.frommatrix(input1);

        in1matrix.op("*",in2matrix);

        //oper.matrixcalc(in1matrix,in2matrix);

        outlet(0,"jit_matrix",in1matrix.name);

        //outlet(0,"jit_matrix",oper.name);

Hmmm...thanks for the reply.  I wouldn't expect it to..."jit.op" isn't initialized like that.  To use jit.op in the context of js, you use op as a method on a matrix. For example, the js equivalent of [jit.op @op *] is below.  
I need a way of expressing per-plane operations in the op method, and putting it operations in an array (e.g. "in1matrix.op(["pass","*","pass","pass"],in2matrix);") doesn't work.

inlets = 2;
var in1matrix = new JitterMatrix(1,"char",320,240);
in1matrix.adapt=1;
var in2matrix = new JitterMatrix(1,"char",320,240);
in1matrix.adapt=1;

function jit_matrix(inname){
	if(inlet==1){
		var input2 = new JitterMatrix(inname);
		in2matrix.frommatrix(input2);
		//outlet(0,"jit_matrix",input2.name);
	}

	if(inlet==0){
		var input1 = new JitterMatrix(inname);
		in1matrix.frommatrix(input1);
		in1matrix.op("*",in2matrix);
		//oper.matrixcalc(in1matrix,in2matrix);
		outlet(0,"jit_matrix",in1matrix.name);
		//outlet(0,"jit_matrix",oper.name);
	}
}


On Jan 27, 2009, at 10:45 AM, pnyboer wrote:

> I wouldn't expect it to..."jit.op" isn't initialized like that. To 

> use jit.op in the context of js, you use op as a method on a matrix. 

> For example, the js equivalent of [jit.op @op *] is below.

JitterMatrix.op() is a convenience method for single operators, but 

for more general use of jit.op you will want to use new 

JitterObject("jit.op") as Joshua suggested:

var myOpper = new JitterMatrix("jit.op");

myOpper.op = ["!pass", "pass", "pass", "pass"];

myOpper.matrixcalc([input1,input2],output);

To do in place processing like your JitterMatrix.op() with a single 

argument, input1 and output would be the same matrix.

> I wouldn't expect it to..."jit.op" isn't initialized like that.  To  
> use jit.op in the context of js, you use op as a method on a matrix.  
> For example, the js equivalent of [jit.op @op *] is below.

JitterMatrix.op() is a convenience method for single operators, but  
for more general use of jit.op you will want to use new  
JitterObject("jit.op") as Joshua suggested:

var myOpper = new JitterMatrix("jit.op");
myOpper.op = ["!pass", "pass", "pass", "pass"];
myOpper.matrixcalc([input1,input2],output);

To do in place processing like your JitterMatrix.op() with a single  
argument, input1 and output would be the same matrix.

Thanks all Joshes for clearing that up. In case there's any confusion when this thread is dug up in a search, it is, of course,

/* the javascript equivalent of [jit.op @op !pass pass pass pass] */

var outmatrix = new JitterMatrix(4,"char",320,240);

opera.op = ["!pass", "pass", "pass", "pass"];

        opera.matrixcalc([input1,in2matrix],input1);

        outlet(0,"jit_matrix",input1.name);

Thanks all Joshes for clearing that up.  In case there's any confusion when this thread is dug up in a search, it is, of course,
new JitterObject("jit.op") 
not new JitterMatrix("jit.op").
Here's a functioning script:

var in2matrix = new JitterMatrix(1,"char",320,240);
in1matrix.adapt=1;
var outmatrix = new JitterMatrix(4,"char",320,240);
outmatrix.adapt=1;
var opera = new JitterObject("jit.op");
opera.op = ["!pass", "pass", "pass", "pass"];

function jit_matrix(inname){
	if(inlet==1){
		var input2 = new JitterMatrix(inname);
		in2matrix.frommatrix(input2);
	}

	if(inlet==0){
		var input1 = new JitterMatrix(inname);
		opera.matrixcalc([input1,in2matrix],input1);
		outlet(0,"jit_matrix",input1.name);
	}
}


multiple ops in jitter javascript