### prependicular vector

hi list, looking to create a vector that will always stay perpendicular to a

specified unit vector. search led me to cross products but as this is a

special case (crossproduct is a product of 2 vector and here the cross of a

vec and its perpendicular brother equals zero) the math is beyond me at this

point. i messed around with a low dim xray.jit.crossproduct but didnt get

far.

any help will be

Well, any vector defines a plane, and within a plane there are an

infinite number of lines/vectors. So, the answer to your question is

that there are an infinite number of perpendicalr vectors to your unit

vector. Now the question is, which one of those will be most useful

to you. Are there any other constraints? If not, then you can treat

the problem in the 2D case such that if you have vector (x, y, z) then

(-y, x, z) will be perpendicular to it.

wes

On 10/14/06, yair reshef

>

> hi list, looking to create a vector that will always stay perpendicular to a

> specified unit vector. search led me to cross products but as this is a

> special case (crossproduct is a product of 2 vector and here the cross of a

> vec and its perpendicular brother equals zero) the math is beyond me at this

> point. i messed around with a low dim xray.jit.crossproduct but didnt get

> far.

> any help will be

>

>

>

>

thnx wesly, that is something neglected to mention, i work with sketch in

2d.

so simple…

2006/10/15, Wesley Smith

>

> Well, any vector defines a plane, and within a plane there are an

> infinite number of lines/vectors. So, the answer to your question is

> that there are an infinite number of perpendicalr vectors to your unit

> vector. Now the question is, which one of those will be most useful

> to you. Are there any other constraints? If not, then you can treat

> the problem in the 2D case such that if you have vector (x, y, z) then

> (-y, x, z) will be perpendicular to it.

>

> wes

>

> On 10/14/06, yair reshef

> >

> > hi list, looking to create a vector that will always stay perpendicular

> to a

> > specified unit vector. search led me to cross products but as this is a

> > special case (crossproduct is a product of 2 vector and here the cross

> of a

> > vec and its perpendicular brother equals zero) the math is beyond me at

> this

> > point. i messed around with a low dim xray.jit.crossproduct but didnt

> get

> > far.

> > any help will be

> >

> >

> >

> >

>

ok, in 2d the perpendicar of (x, y) is (-y, x) or (y, -x).

wes

On 10/14/06, yair reshef

>

> thnx wesly, that is something neglected to mention, i work with sketch in

> 2d.

> so simple…

>

>

> 2006/10/15, Wesley Smith < wesley.hoke@gmail.com>:

> > Well, any vector defines a plane, and within a plane there are an

> > infinite number of lines/vectors. So, the answer to your question is

> > that there are an infinite number of perpendicalr vectors to your unit

> > vector. Now the question is, which one of those will be most useful

> > to you. Are there any other constraints? If not, then you can treat

> > the problem in the 2D case such that if you have vector (x, y, z) then

> > (-y, x, z) will be perpendicular to it.

> >

> > wes

> >

> > On 10/14/06, yair reshef < yair99@gmail.com> wrote:

> > >

> > > hi list, looking to create a vector that will always stay perpendicular

> to a

> > > specified unit vector. search led me to cross products but as this is a

> > > special case (crossproduct is a product of 2 vector and here the cross

> of a

> > > vec and its perpendicular brother equals zero) the math is beyond me at

> this

> > > point. i messed around with a low dim xray.jit.crossproduct but didnt

> get

> > > far.

> > > any help will be

> > >

> > >

> > >

> > >

> >

>

>

>

>

>

hello

i built a-perp, which calculates the perpendicular vectors

here’s the main loop it executes

void perp_calc (perp *x)

{

/*

P – 1/||q||^2 * [1x3]matrix

*/

short i;

float qx2, qxqy, qyqz, qxqz,

qy2,

qz2,

px, py, pz,

qx, qy, qz,

normq;

float temp[3];

t_atom *o;

o = x->perp;

qx = x->q[0];

qy = x->q[1];

qz = x->q[2];

px = x->p[0];

py = x->p[1];

pz = x->p[2];

qx2=qx*qx;

qy2=qy*qy;

qz2=qz*qz;

qxqy=qx*qy;

qyqz=qy*qz;

qxqz=qx*qz;

// 1/||q||^2

normq= (sqrt(qx*qx+qy*qy*qz*qz));

normq= normq*normq;

if (normq==0.) {

;

} else {

normq= 1./normq;

}

// matrix calcs projection

temp[0] = qx2*px + qxqy*py + qxqz*pz;

temp[1] = qxqy*px + qy2*py + qyqz*pz;

temp[2] = qxqz*px + qyqz*py + qz2*pz;

temp[0] = temp[0] * normq;

temp[1] = temp[1] * normq;

temp[2] = temp[2] * normq;

// p – projqP

sub(temp, x->p, temp);

for(i=0;i<3;i++) {

SETFLOAT(o+i, temp[i]);

}

outlet_list(x->c_out, 0L, 3, o);

}

this is a part of my a-objects, still in beta 7 i believe

http://www.s373.net/code

cheers

a

On 2006, Oct, 15 , at 12:37 , yair reshef wrote:

> hi list, looking to create a vector that will always stay

> perpendicular to a specified unit vector. search led me to cross

> products but as this is a special case (crossproduct is a product

> of 2 vector and here the cross of a vec and its perpendicular

> brother equals zero) the math is beyond me at this point. i messed

> around with a low dim xray.jit.crossproduct but didnt get far.

> any help will be

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