[+~] with [delay~] and feedback doesn't work
Jan 24 2014 | 12:20 am
Hello,
I am trying to make an audio rate counter. If I connect [sig~ 1] to a [+~] and the outlet of the [+~] to a [delay~ 1 1] and then back into the right inlet of the [+~], I would expect the output to be 1 higher every time.
But, it doesn't work. Why not? Is this because of signal vector things?
Thanks in advance!
Boris
- Jan 24 2014 | 4:06 pmYou can't have a loop in DSP chain. Try with tap{in,out}~, but keep in mind it will (at best) count vectors, not samples. Look up +=~, and of course gen~ is natural environment for this kind of processing.
- Jan 25 2014 | 1:04 amit works fine with a send~ and receive~ object. just place the output of the delay to the send~ and the receive~ back into the delay~like this
- Jan 25 2014 | 6:42 pmThat's because a send~ receive~ pair automatically introduces a sample's delay. It will still work obviously but it's just something to bare in mind if you want sample precision.
- Jan 26 2014 | 5:44 amAh no kidding? Well that's useful to know in the future. Thanks!
- Jan 26 2014 | 1:10 pmJust to clarify, in this case (because there's a loop), send~/receive~ introduce one "signal vector" of delay.
- Jan 27 2014 | 7:29 amI might be oversimplifying here but if your goal is to have an audio rate counter checking out the [count~] object might be useful.- Luigi
