Averaging lists
I have 4 lists with 12,000 items each.
I want a new list of the same size, with the averaged values.
Can I do this in one go without cycling through the items and averaging 4 at a time? I know how to do that, but maybe I can do it directly with a magic object ...
custom cross sum based on [accum]?
as long as cross sum is not greater than 64 bit´s max... ;)
Ah ...
Huh?
I don't understand a word :-)
4 lists, each with 12,000 items.
At the moment I break the 4 lists into 4 colls,
uzi 12,000 x 4 coll lines,
pack them,
zl.median,
zl.group 12000
I would be interested in a shorter way.
Seems to be working, but not sure if shorter in the end ;-) :
Not tried yet, but I think this exceeds the 32,676 zlmaxsize.
zl.lace for 2 lists with 12,000 items each would need a zlmaxsize of 24,000, correct?
Then
zl.lace 1 & 2 = 24,000 items
zl.lace 3 & 4 = 24,000 items
Then the target zl.lace combines that to 48,000 items, correct?
Too long.
I think I could work around in two stages but then you are right, it's probably not shorter in the end.
Correct. I overlooked the 24000 items (not used to manipulating lists of that size !).
This one, avoiding combinations of lists, maybe ?
Looks good.
I tried already with zl.nth but did not think of parallel processing.
This one should work better than my colls.
Thank you!
Can I do this in one go without cycling through the items and averaging 4 at a time?
Yes, I think it is the ideal situation from a logical and performance point of view.
I would suggest Jitter for that, use a matrix as a list.
See the attached patch, I think the performance is very good.
See the attached patch, I think the performance is very good.Oh, that's really cool !
Wow, the solution for adults.
I'm impressed. Thank you very much!
I will probably jitter a little in future. Knowing how to deal with lots of pixels really helps ...
re:accum
iterate the list, run the values into [accum], divide their sum through number of elements = avg value
(i.e. without the need to do list processing.)
Nitpicking here but with large amounts of data it will have an impact: If you can, avoid division and use a multiplier instead
(in[0].p[0]+in[0].p[1]+in[0].p[2]+in[0].p[3])*0.25
<pre><code>
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-----------end_max5_patcher-----------
</code></pre>
<Edit> It won't let me conveniently paste the patch in the post so it comes up as a single button? Normally that happens automatic