Scale with a 'mid-point', and without a curve
drico
9月 11 2024 | 9:31 午前
Beginner here. How can I scale and set a "midpoint"?
Let's say I'm using 0–1 float as my input, where naturally the midpoint would be .50. How can I designate a midpoint of .20
Most importantly, the issue I'm running into is that I want the 'curve' to be completely linear, so really no curve at all.
I'm finding that using the scale object with exponential values or the linedrive object creates a curve.
Roman Thilenius
9月 11 2024 | 7:48 午後
first split the input range into halves, then scale them individually:
in extreme use cases you might need to split and process the center value from the rest in addition. for this, see below, as it wont work using [split]
full set of modular range mapping patches: https://cycling74.com/forums/re-mapping-a-range-of-numbers-add-your-tricks-here#reply-58ed20de6908cf22c8392910
Source Audio
9月 12 2024 | 9:57 午前
scale is linear if no exponential value is set.