Scale with a 'mid-point', and without a curve

drico's icon

drico

9月 11 2024 | 9:31 午前

Beginner here. How can I scale and set a "midpoint"?

Let's say I'm using 0–1 float as my input, where naturally the midpoint would be .50. How can I designate a midpoint of .20

Most importantly, the issue I'm running into is that I want the 'curve' to be completely linear, so really no curve at all.

I'm finding that using the scale object with exponential values or the linedrive object creates a curve.

Roman Thilenius's icon

Roman Thilenius

9月 11 2024 | 7:48 午後

first split the input range into halves, then scale them individually:

in extreme use cases you might need to split and process the center value from the rest in addition. for this, see below, as it wont work using [split]

Source Audio's icon

Source Audio

9月 12 2024 | 9:57 午前

scale is linear if no exponential value is set.