Masa

Hi all, I have got a message object containing:

replace "Macintosh HD:/Users/k/Documents/Max 7/Projects/km.performance/media/time_bass_bpm110.aif"

I am trying to extract '110' from this type of message, the integer just after 'bpm'.

I tried 'regexp \\d+', but it extracts '7 110' instead of '110.

The number of integers in the path varies from time to time.

Very many thanks for your help in advance,

Hi all, I have got a message object containing:
replace "Macintosh HD:/Users/k/Documents/Max 7/Projects/km.performance/media/time_bass_bpm110.aif"

I am trying to extract '110' from this type of message, the integer just after 'bpm'.
I tried 'regexp \\d+', but it extracts '7 110' instead of '110.
The number of integers in the path varies from time to time.
I appreciate your advice.

Very many thanks for your help in advance,
Masa

how-would-you-extract-the-letters-after-x-from-a-message-object

Much closer now with 'regexp bpm(.+)\\d'
But it outputs '11' instead of '110'.

OK, it does not look clean, but I used 'regexp bpm(.+)' and 'regexp \\d+' in serial.

How could I learn the behaviour of regexp in general? The help and the reference pages are not detailed enough.

Thanks a lot BROC. This is beautiful.
How could I learn the behaviour of regexp in general? The help and the reference pages are not detailed enough.


How would you extract the letters after X from a message object?