mc.*~ deviate by integer range not float range

    Matt Romein
    Dec 06 2018 | 9:08 pm
    Curious if there's a way to use the deviate message to specify only deviating between integers rather than floats. I want an incoming sig~ value to be multiplied by a deviating integer. Right now when I use deviate it only seems to allow for a deviation of values in a float range. Is there a way to change that behavior of deviate. The final value may still be a float since the sig~ value is a float, I just want to make sure it's only multiplied by an integer. Patch attached to explain further.
    • testcase
      Dec 06 2018 | 10:27 pm
      think you might need to insert something like [mc.round~ 1 @nearest 0] after the [mc.*~ @chans 4] object
    • Matt Romein
      Dec 06 2018 | 10:36 pm
      I don't think that quite works. From what I can see it only allows me to round the values coming out of the mc.*~ object. I still need the object to return floats but what I'm hoping is to find a way where the deviation values are always truncated.
      For example if the sig~ was a value of 0.5 and I used mc.*~ with a (deviate 2 2) message it would only return either, 0, 0.5, 1.0, 1.5, or 2.0. Right now (deviate 2 2) gives me any float value between 0.0 and 4.0.
    • testcase
      Dec 06 2018 | 10:53 pm
      ah i see. i don't think there is a way to do it with the deviate message to mc.*~ but i think you can do something like this:
    • Matt Romein
      Dec 06 2018 | 10:56 pm
      Ahh that's exactly it. I was focused on changing the behavior of deviate I didn't think about how I could achieve it before I got to the mc.*~ object. Thank you!